8. Merge Sorted Array
easyAsked at BookingMerge two sorted arrays in-place — Booking tests this to see if you can fold a supplier price update into the master availability array without extra memory.
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Problem
Given two sorted arrays nums1 (size m+n, with trailing zeros) and nums2 (size n), merge nums2 into nums1 as one sorted array in-place.
Constraints
nums1.length == m + nnums2.length == n0 <= m, n <= 200
Examples
Example 1
nums1 = [1,2,3,0,0,0], m=3, nums2 = [2,5,6], n=3[1,2,2,3,5,6]Example 2
nums1 = [1], m=1, nums2 = [], n=0[1]Approaches
1. Brute force concat-sort
Copy nums2 into nums1 and call sort.
- Time
- O((m+n) log(m+n))
- Space
- O(1)
for (let i=0;i<n;i++) nums1[m+i] = nums2[i];
nums1.sort((a,b)=>a-b);Tradeoff:
2. Three pointers from the back
Compare from the back and write into the tail — avoids overwriting unread cells.
- Time
- O(m+n)
- Space
- O(1)
function merge(nums1, m, nums2, n) {
let i = m - 1, j = n - 1, k = m + n - 1;
while (j >= 0) {
if (i >= 0 && nums1[i] > nums2[j]) {
nums1[k--] = nums1[i--];
} else {
nums1[k--] = nums2[j--];
}
}
}Tradeoff:
Booking-specific tips
Booking handles supplier-fanout merges constantly — explain how the from-the-back pointer pattern avoids the doubled buffer you would need at supplier scale.
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