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12. Maximum Depth of Binary Tree

easyAsked at Chegg

Find the maximum depth of a binary tree — tests tree recursion fundamentals that underpin Chegg's content hierarchy traversal.

By Alex Chen, Founder, InterviewChamp.AI · Last verified

Problem

Given the root of a binary tree, return its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Return 0 for an empty tree.

Constraints

  • Number of nodes in the range [0, 10^4]
  • -100 <= Node.val <= 100

Examples

Example 1

Input
root = [3,9,20,null,null,15,7]
Output
3

Example 2

Input
root = [1,null,2]
Output
2

Approaches

1. Brute force

Iterative BFS counting levels.

Time
O(n)
Space
O(n)
function maxDepth(root) {
  if (!root) return 0;
  const queue = [root];
  let depth = 0;
  while (queue.length) {
    depth++;
    const size = queue.length;
    for (let i = 0; i < size; i++) {
      const node = queue.shift();
      if (node.left) queue.push(node.left);
      if (node.right) queue.push(node.right);
    }
  }
  return depth;
}

Tradeoff:

2. Recursive DFS

Return 1 + max of left and right subtree depths. The base case is null returning 0, making the recursion naturally elegant.

Time
O(n)
Space
O(h) where h is tree height
function maxDepth(root) {
  if (!root) return 0;
  return 1 + Math.max(maxDepth(root.left), maxDepth(root.right));
}

Tradeoff:

Chegg-specific tips

Chegg values clean recursive thinking here — interviewers relate this to traversing nested content category trees in their ed-tech recommendation engine.

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