4. Remove Duplicates from Sorted Array
easyAsked at CoupangIn-place dedupe of a sorted array — Coupang asks this to test pointer-pair fluency before SKU-list deduplication problems.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. Return the number of unique elements k.
Constraints
1 <= nums.length <= 3 * 10^4-100 <= nums[i] <= 100nums is sorted
Examples
Example 1
nums = [1,1,2]2, nums = [1,2,_]Example 2
nums = [0,0,1,1,1,2,2,3,3,4]5, nums = [0,1,2,3,4,...]Approaches
1. Brute force
Build a Set, copy back.
- Time
- O(n)
- Space
- O(n)
const s=[...new Set(nums)];
for(let i=0;i<s.length;i++) nums[i]=s[i];
return s.length;Tradeoff:
2. Two pointers
Slow pointer marks write position; fast pointer scans.
- Time
- O(n)
- Space
- O(1)
function removeDuplicates(nums) {
if (nums.length === 0) return 0;
let k = 1;
for (let i = 1; i < nums.length; i++) {
if (nums[i] !== nums[i - 1]) {
nums[k++] = nums[i];
}
}
return k;
}Tradeoff:
Coupang-specific tips
Coupang weighs in-place O(1) space heavily because their warehouse SKU pipelines run on memory-constrained edge nodes.
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