6. Search Insert Position
easyAsked at CourseraFind the insert index in a sorted array — Coursera tests binary-search invariants for ordered course-catalog inserts.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a sorted array of distinct integers and a target, return the index if found. If not, return the index where it would be inserted to keep the array sorted.
Constraints
1 <= nums.length <= 10^4-10^4 <= nums[i], target <= 10^4nums is sorted ascending with no duplicates
Examples
Example 1
nums = [1,3,5,6], target = 52Example 2
nums = [1,3,5,6], target = 21Approaches
1. Linear scan
Walk until first nums[i] >= target.
- Time
- O(n)
- Space
- O(1)
for (let i = 0; i < nums.length; i++)
if (nums[i] >= target) return i;
return nums.length;Tradeoff:
2. Binary search lower bound
Standard half-open lo/hi loop; return lo at end.
- Time
- O(log n)
- Space
- O(1)
function searchInsert(nums, target) {
let lo = 0, hi = nums.length;
while (lo < hi) {
const mid = (lo + hi) >> 1;
if (nums[mid] < target) lo = mid + 1;
else hi = mid;
}
return lo;
}Tradeoff:
Coursera-specific tips
Coursera asks you to defend your binary-search invariants out loud — they have been burned by off-by-one bugs in the course-catalog insertion path before.
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