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Datadog Coding Interview Questions

100 Datadog coding interview problems with full optimal solutions — 31 easy, 54 medium, 15 hard. Every problem ships with multiple approaches (brute-force first, then the optimal), complexity tables for each, company-specific tips on what an Datadog interviewer values, and a FAQ section.

Showing 32 problems of 100

  • #33mediumsometimes asked

    33. Longest Palindromic Substring

    Find the longest palindromic substring. Datadog asks this for the expand-around-center pattern — O(n^2) time with O(1) space, a sweet spot for streaming validators that can't afford O(n) extra memory.

  • #34mediumsometimes asked

    34. Container With Most Water

    Find two heights that form a container holding the most water. Datadog asks this for the two-pointer-greedy proof — the same kind of monotone-invariant reasoning needed for windowed peak detection on metric streams.

  • #36mediumsometimes asked

    36. Letter Combinations of a Phone Number

    Generate all possible letter combinations for a phone-keypad number. Datadog uses this as a backtracking warmup — same recursive-emission structure as their downsampling rollup that enumerates resolution buckets.

  • #37mediumsometimes asked

    37. Remove Nth Node From End of List

    Remove the Nth-from-end node in a singly linked list in one pass. Datadog tests the two-pointer-offset trick — the same pattern they use to maintain a fixed-lag window over a streaming sequence.

  • #38mediumsometimes asked

    38. Generate Parentheses

    Generate all combinations of n well-formed parentheses. Datadog asks this for the backtracking constraint-pruning pattern — the same idea applied to enumerating valid log-parser states.

  • #39mediumrarely asked

    39. Swap Nodes in Pairs

    Swap every two adjacent nodes in a linked list, in place. Datadog uses this to test pointer-manipulation discipline before harder variants like reverse-in-groups.

  • #40mediumrarely asked

    40. Next Permutation

    Rearrange numbers into the lexicographically next greater permutation. Datadog uses this as a deep array-manipulation question — the algorithmic clarity is similar to the cursor-advance logic in their iterator-based query layer.

  • #43mediumrarely asked

    43. Valid Sudoku

    Validate a 9x9 Sudoku board against the row/col/box rules in a single pass. Datadog asks this because the constraint-encoding trick (one Set per row/col/box) is the same shape as validating multi-dimensional metric tags in a single ingestion pass.

  • #44mediumsometimes asked

    44. Combination Sum

    Find all unique combinations of candidate integers that sum to target, with reuse allowed. Datadog asks this for the backtracking-with-reuse pattern — same shape as expanding multi-resolution rollup partitions.

  • #45mediumsometimes asked

    45. Permutations

    Generate all permutations of a distinct-integer array. Datadog uses this as a baseline backtracking question — and follows up by asking how to lazily yield permutations as an iterator over a streaming consumer.

  • #46mediumsometimes asked

    46. Rotate Image

    Rotate an N x N matrix 90 degrees clockwise in place. Datadog tests this for the transpose-plus-reverse trick — same shape as their column-store to row-store flip during chunk compaction.

  • #48mediumrarely asked

    48. Spiral Matrix

    Traverse an M x N matrix in spiral (clockwise) order. Datadog uses this as a 2D-traversal warmup to test boundary-management discipline — the same shape as iterating over a chunked time-series block with varying boundaries.

  • #51mediumsometimes asked

    51. Unique Paths

    Count paths from top-left to bottom-right of an m x n grid, moving only right or down. Datadog asks this as a DP-fundamentals warmup before harder grid problems with constraints.

  • #52mediumsometimes asked

    52. Minimum Path Sum

    Find the minimum-cost path from top-left to bottom-right of a grid, moving only right or down. Datadog uses this as a weighted-DP foundation before harder pathfinding questions.

  • #53mediumsometimes asked

    53. Simplify Path

    Convert a Unix-style absolute path into its canonical form. Datadog uses this for the stack-based path-segment pattern — same shape as their tag-prefix normalization for hierarchical metric names.

  • #54mediumsometimes asked

    54. Edit Distance

    Compute the minimum number of insert/delete/replace operations to convert one string into another (Levenshtein distance). Datadog asks this for the classic 2D DP — same recurrence they use when diffing two metric-name versions during schema migration.

  • #55mediumrarely asked

    55. Set Matrix Zeroes

    Given an m x n matrix, if an element is 0, set its entire row and column to 0 — in place, O(1) extra space. Datadog asks this for the encode-state-in-matrix trick — same shape as their in-place chunk-level invalidation marks during compaction.

  • #56mediumsometimes asked

    56. Search a 2D Matrix

    Search for a target in a row-sorted matrix where the first element of each row > the last element of the previous row. Datadog asks this to verify you spot the flatten-to-1D trick — same shape as indexing a packed sorted block as if it were a flat array.

  • #58mediumsometimes asked

    58. Subsets

    Return all subsets of a distinct-integer array (the power set). Datadog uses this as a backtracking foundation, and probes you to discuss bitmask enumeration as an alternative.

  • #59mediumsometimes asked

    59. Word Search

    Determine if a word exists in a 2D board where adjacent cells form a path. Datadog uses this for the DFS-with-backtracking pattern — same shape as searching for a metric-name pattern in a hierarchical store.

  • #60mediumsometimes asked

    60. Decode Ways

    Count the number of ways to decode a digit string into letters (A=1, B=2, ..., Z=26). Datadog asks this for the 1D DP pattern — same shape as their dynamic-parser that branches on ambiguous log-line prefixes.

  • #63mediumsometimes asked

    63. Binary Tree Zigzag Level Order Traversal

    Return a binary tree's level-order traversal but alternate left-to-right and right-to-left per level. Datadog uses this BFS variant to test that you can compose direction-flipping on top of the level-batch primitive.

  • #66mediumsometimes asked

    66. Path Sum II

    Find all root-to-leaf paths where the sum equals a target. Datadog uses this for backtracking with path tracking — same shape as enumerating valid traces through a service-dependency graph.

  • #69mediumsometimes asked

    69. Copy List with Random Pointer

    Deep-copy a linked list where each node has both a next pointer and a random pointer to any node. Datadog uses this for the old-to-new mapping trick — same shape as their snapshot logic for a graph with arbitrary edges.

  • #70mediumsometimes asked

    70. Word Break

    Given a string and a dictionary, determine if the string can be segmented into a sequence of dictionary words. Datadog uses this for the 1D DP segmentation pattern — same shape as their tokenizer for tag-pattern matching on hierarchical metric names.

  • #72mediumsometimes asked

    72. Sort List

    Sort a linked list in O(n log n) time and O(1) extra space. Datadog asks this for the bottom-up merge-sort pattern — same shape as their external-sort routine over chunked metric files.

  • #73mediumsometimes asked

    73. Maximum Product Subarray

    Find the contiguous subarray with the largest product. Datadog asks this for the dual-track DP trick (track both min and max) — same shape as anomaly detection that must handle bidirectional outliers.

  • #75mediumsometimes asked

    75. Find Peak Element

    Find any peak element in O(log n). Datadog asks this for the non-monotonic binary-search pattern — peak detection in metric streams uses the same uphill-direction logic.

  • #76mediumsometimes asked

    76. Find the Duplicate Number

    Find the single duplicate in an array of n+1 integers where each is in [1, n]. Datadog asks this for the Floyd-tortoise-on-implicit-cycle trick — finding a duplicate metric ID in O(n) time, O(1) memory.

  • #82mediumsometimes asked

    82. House Robber

    Max-sum subsequence with no two adjacent elements. Datadog uses this as the simplest 1D DP question — same shape as their non-overlapping window aggregation over a metric stream.

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