2. Valid Parentheses
easyAsked at DropboxDetermine if a string of brackets is balanced; Dropbox uses this to probe stack reasoning for nested file-tree path parsing.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a string containing just '(', ')', '{', '}', '[', ']', determine if it is valid. Open brackets must be closed by the same type and in the correct order.
Constraints
1 <= s.length <= 10^4s consists of bracket characters only
Examples
Example 1
s="()[]{}"trueExample 2
s="(]"falseApproaches
1. Brute force
Repeatedly strip innermost pairs until none remain.
- Time
- O(n^2)
- Space
- O(n)
while (s.includes('()')||s.includes('[]')||s.includes('{}'))
s = s.replace('()','').replace('[]','').replace('{}','');
return s.length===0;Tradeoff:
2. Stack
Push openings; on closing, pop and verify it matches. Linear single pass.
- Time
- O(n)
- Space
- O(n)
function isValid(s) {
const pair = { ')': '(', ']': '[', '}': '{' };
const stack = [];
for (const c of s) {
if (c in pair) {
if (stack.pop() !== pair[c]) return false;
} else stack.push(c);
}
return stack.length === 0;
}Tradeoff:
Dropbox-specific tips
Dropbox interviewers expect you to call out empty-stack-on-close as a separate edge case — they map it to malformed path segments in the sync protocol.
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