3. Merge Two Sorted Lists
easyAsked at ExpediaMerge two sorted linked lists into one sorted linked list.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
You are given the heads of two sorted linked lists list1 and list2. Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
Constraints
0 <= count of nodes <= 50-100 <= Node.val <= 100Both lists sorted ascending
Examples
Example 1
list1 = [1,2,4], list2 = [1,3,4][1,1,2,3,4,4]Example 2
list1 = [], list2 = [][]Approaches
1. Collect and sort
Dump both into an array, sort, rebuild.
- Time
- O((n+m) log(n+m))
- Space
- O(n+m)
const arr = [];
while (l1) { arr.push(l1.val); l1 = l1.next; }
while (l2) { arr.push(l2.val); l2 = l2.next; }
arr.sort((a,b)=>a-b);Tradeoff:
2. Two-pointer merge
Walk both lists, append smaller node to result. Expedia uses this exact technique to merge sorted hotel-rate feeds from competing suppliers.
- Time
- O(n+m)
- Space
- O(1)
function mergeTwoLists(l1, l2) {
const dummy = { val: 0, next: null };
let tail = dummy;
while (l1 && l2) {
if (l1.val <= l2.val) { tail.next = l1; l1 = l1.next; }
else { tail.next = l2; l2 = l2.next; }
tail = tail.next;
}
tail.next = l1 || l2;
return dummy.next;
}Tradeoff:
Expedia-specific tips
Expedia interviewers will probe how you'd extend this to k sorted streams — a direct analog to merging price feeds from k supplier APIs.
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