24. Merge K Sorted Lists
hardAsked at GitHubMerge k sorted linked lists into one sorted list using a min-heap, analogous to how GitHub merges multiple sorted commit streams from different remotes during a fetch.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an array of k linked-list heads, where each linked list is sorted in ascending order, merge all the linked-lists into one sorted linked-list and return it.
Constraints
k == lists.length0 <= k <= 10^40 <= lists[i].length <= 500-10^4 <= lists[i][j] <= 10^4
Examples
Example 1
lists = [[1,4,5],[1,3,4],[2,6]][1,1,2,3,4,4,5,6]Example 2
lists = [][]Approaches
1. Brute force: collect and sort
Flatten all nodes into an array, sort, then rebuild list — loses linked-list structure advantages.
- Time
- O(N log N)
- Space
- O(N)
// Collect all .val into array, sort, rebuild ListNode chain
// Simple but doesn't demonstrate priority-queue skillTradeoff:
2. Min-heap (priority queue)
Seed a min-heap with each list's head. Pop the minimum node, append to result, push its next node into heap. Repeat until heap is empty — O(N log k) by keeping heap size at most k.
- Time
- O(N log k)
- Space
- O(k)
// JavaScript lacks a built-in heap; simulate with sorted array (ok for interviews)
function mergeKLists(lists) {
const dummy = new ListNode(0);
let curr = dummy;
// Min-heap of [node.val, node]
const heap = [];
for (const head of lists) if (head) heap.push(head);
heap.sort((a,b)=>a.val-b.val);
while (heap.length) {
const min = heap.shift();
curr.next = min;
curr = curr.next;
if (min.next) {
// Insert min.next in sorted position
let i = 0;
while (i < heap.length && heap[i].val <= min.next.val) i++;
heap.splice(i, 0, min.next);
}
}
return dummy.next;
}Tradeoff:
GitHub-specific tips
GitHub merges sorted commit-timestamp streams during fetch and rebase operations; explain the heap invariant clearly and note that in production you'd use a proper MinHeap class for O(log k) push/pop rather than splice.
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