48. Rotate Image
mediumAsked at RedditRotate an n x n matrix 90 degrees clockwise in-place. Reddit asks this to test the transpose-then-reverse trick — the same building block they use when re-orienting heatmap matrices for moderator dashboards.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Source citations
Public interview reports confirming this problem appears in Reddit loops.
- Glassdoor (2026-Q1)— Reddit phone screen for backend roles.
Problem
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise). You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Constraints
n == matrix.length == matrix[i].length1 <= n <= 20-1000 <= matrix[i][j] <= 1000
Examples
Example 1
matrix = [[1,2,3],[4,5,6],[7,8,9]][[7,4,1],[8,5,2],[9,6,3]]Example 2
matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]][[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]Approaches
1. Copy to new matrix
Compute new[j][n-1-i] = matrix[i][j].
- Time
- O(n^2)
- Space
- O(n^2)
// Anti-pattern: violates in-place constraint.Tradeoff: Fails the in-place requirement.
2. Transpose + reverse rows (optimal)
First transpose (swap matrix[i][j] with matrix[j][i]), then reverse each row.
- Time
- O(n^2)
- Space
- O(1)
function rotate(matrix) {
const n = matrix.length;
// Transpose
for (let i = 0; i < n; i++) {
for (let j = i + 1; j < n; j++) {
[matrix[i][j], matrix[j][i]] = [matrix[j][i], matrix[i][j]];
}
}
// Reverse each row
for (let i = 0; i < n; i++) matrix[i].reverse();
}Tradeoff: O(1) extra. Two simple passes are clearer than one tricky 4-cell rotation.
Reddit-specific tips
Reddit interviewers will accept either the transpose+reverse or the 4-cell rotation. Bonus signal: explain WHY transpose+reverse works — matrix transpose plus horizontal flip equals 90° CW rotation. Mention the counter-clockwise variant uses transpose+reverse-cols.
Common mistakes
- Looping j from 0 to n in the transpose step (double-swaps and undoes itself). Use j = i + 1.
- Reversing columns instead of rows (gives counter-clockwise).
- Allocating a new matrix and pretending it's in-place.
Follow-up questions
An interviewer at Reddit may pivot to one of these next:
- Rotate 180 degrees — reverse rows then reverse cols.
- Spiral matrix (LC 54).
- Rotate counter-clockwise 90.
Solve it now
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FAQ
Why j = i + 1 in transpose?
Swapping (i, j) and (j, i) is symmetric — doing it twice undoes it. Only swap the upper triangle.
Alternative algorithm?
Rotate four cells at a time — (i, j), (j, n-1-i), (n-1-i, n-1-j), (n-1-j, i). Equivalent but harder to code without bugs.
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