2. Valid Parentheses
easyAsked at RobloxDetermine if a string of brackets is properly opened and closed in the correct order.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. Brackets must close in the correct order and every opener must have a matching closer.
Constraints
1 <= s.length <= 10^4s consists of bracket characters only
Examples
Example 1
s = "()[]{}"trueExample 2
s = "(]"falseApproaches
1. Brute force replace
Repeatedly remove matched pairs until no change.
- Time
- O(n^2)
- Space
- O(n)
while (s.includes('()') || s.includes('[]') || s.includes('{}')) {
s = s.replace('()','').replace('[]','').replace('{}','');
}
return s.length === 0;Tradeoff:
2. Stack
Push openers, pop and compare on closers. Empty stack at end means valid.
- Time
- O(n)
- Space
- O(n)
function isValid(s) {
const pair = { ')':'(', ']':'[', '}':'{' };
const stack = [];
for (const c of s) {
if (c in pair) {
if (stack.pop() !== pair[c]) return false;
} else {
stack.push(c);
}
}
return stack.length === 0;
}Tradeoff:
Roblox-specific tips
Roblox uses this to gauge stack fluency before exploring how you would parse Luau script tokens or nested Roblox Studio property trees.
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