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12. Maximum Depth of Binary Tree

easyAsked at Salesforce

Return the maximum depth (number of nodes along the longest root-to-leaf path) of a binary tree. Salesforce asks this to verify clean recursion — relevant to their role-hierarchy depth queries.

By Alex Chen, Founder, InterviewChamp.AI · Last verified

Source citations

Public interview reports confirming this problem appears in Salesforce loops.

  • Glassdoor (2026-Q1)Used on Salesforce backend phone screens as a tree-recursion baseline.
  • Blind (2025-08)Asked alongside role-hierarchy depth limit discussions.

Problem

Given the root of a binary tree, return its maximum depth. A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Constraints

  • The number of nodes in the tree is in the range [0, 10^4].
  • -100 <= Node.val <= 100

Examples

Example 1

Input
root = [3,9,20,null,null,15,7]
Output
3

Example 2

Input
root = [1,null,2]
Output
2

Approaches

1. BFS level count

Level-order traversal; count the number of levels.

Time
O(n)
Space
O(w) where w is max width
function maxDepth(root) {
  if (!root) return 0;
  const queue = [root];
  let depth = 0;
  while (queue.length) {
    const next = [];
    for (const node of queue) {
      if (node.left) next.push(node.left);
      if (node.right) next.push(node.right);
    }
    queue.splice(0, queue.length, ...next);
    depth++;
  }
  return depth;
}

Tradeoff: Works but verbose. Use when you also need level-by-level data; otherwise prefer DFS.

2. Recursive DFS

Depth = 1 + max(depth of left, depth of right). Null = 0.

Time
O(n)
Space
O(h)
function maxDepth(root) {
  if (!root) return 0;
  return 1 + Math.max(maxDepth(root.left), maxDepth(root.right));
}

Tradeoff: Three lines of clean recursion. The base case (null = 0) makes the recursion compose correctly.

Salesforce-specific tips

Salesforce role-hierarchy has a documented depth limit (8 levels in production), so they grade this problem on whether your solution scales to that — both versions do, but the DFS is what they expect. Bonus signal: mention iterative DFS with explicit stack when asked about avoiding recursion limits.

Common mistakes

  • Returning Math.max(maxDepth(left), maxDepth(right)) without +1 — gives depth - 1.
  • Returning 1 for null instead of 0 — gives off-by-one.
  • Forgetting the null check at root entry — crashes on empty tree.

Follow-up questions

An interviewer at Salesforce may pivot to one of these next:

  • Minimum Depth of Binary Tree (LC 111).
  • Balanced Binary Tree (LC 110) — uses max depth as a subroutine.
  • Diameter of Binary Tree (LC 543) — pairs depth tracking with global max.

Solve it now

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Output

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FAQ

Why is the recursion 3 lines but BFS is 12?

DFS leverages the call stack as an implicit recursion structure; BFS needs explicit queue management. For pure depth, the explicit structure is overhead.

What if the tree is a million nodes deep (skewed)?

The recursive DFS overflows the call stack. Switch to iterative DFS with an explicit stack, or use Morris-style traversal.

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