11. Climbing Stairs
easyAsked at SnapCount distinct ways to climb n stairs taking 1 or 2 steps at a time. Snap uses this as a 'do you spot Fibonacci' check before harder DP.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Source citations
Public interview reports confirming this problem appears in Snap loops.
- Glassdoor (2026-Q1)— Listed as a Snap warm-up to gauge DP intuition.
- LeetCode Discuss (2025)— Frequently bundled with Fibonacci in Snap intern screens.
Problem
You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Constraints
1 <= n <= 45
Examples
Example 1
n = 22Explanation: Two ways: 1+1 or 2.
Example 2
n = 33Explanation: 1+1+1, 1+2, or 2+1.
Approaches
1. Naive recursion
f(n) = f(n-1) + f(n-2) with no memoization.
- Time
- O(2^n)
- Space
- O(n)
function climbStairs(n) {
if (n <= 2) return n;
return climbStairs(n - 1) + climbStairs(n - 2);
}Tradeoff: Exponential and re-computes the same subproblems. Use only to motivate memoization.
2. Bottom-up two-variable DP (optimal)
Maintain (prev2, prev1) representing f(i-2), f(i-1). Each step compute curr = prev2 + prev1, then shift.
- Time
- O(n)
- Space
- O(1)
function climbStairs(n) {
if (n <= 2) return n;
let prev2 = 1;
let prev1 = 2;
for (let i = 3; i <= n; i++) {
const curr = prev2 + prev1;
prev2 = prev1;
prev1 = curr;
}
return prev1;
}Tradeoff: Linear time, constant space. Mirrors Fibonacci exactly — name that out loud.
Snap-specific tips
At Snap, identify the Fibonacci recurrence before coding. Bonus signal: when asked about following up with arbitrary steps, mention coin-change DP — Snap interviewers like to escalate this into a 'count ways under constraint' problem.
Common mistakes
- Allocating an O(n) DP array when two variables suffice.
- Off-by-one on base cases — confirm f(1)=1 and f(2)=2.
- Mutating prev1 before reading it in the next step.
Follow-up questions
An interviewer at Snap may pivot to one of these next:
- Steps of size 1, 2, or 3.
- Steps from an arbitrary set (coin-change variant).
- Min-cost climbing stairs (LC 746).
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FAQ
Why is the answer Fibonacci?
Because at step i you either came from step i-1 (one step) or step i-2 (two steps), so f(i) = f(i-1) + f(i-2).
Is the matrix-power O(log n) solution worth mentioning?
Yes for bonus — but only after you've delivered the O(n) baseline. Snap usually doesn't require it unless n becomes astronomical.
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