14. Minimum Depth of Binary Tree
easyAsked at TeslaFind the minimum number of nodes on a path from root to leaf.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given the root of a binary tree, return its minimum depth — the shortest path from root to any leaf in terms of node count.
Constraints
0 <= node count <= 10^5-1000 <= node.val <= 1000
Examples
Example 1
root = [3,9,20,null,null,15,7]2Example 2
root = [2,null,3,null,4,null,5,null,6]5Approaches
1. Naive recursion
Min over both children — careful with the single-child edge case.
- Time
- O(n)
- Space
- O(h)
function minDepth(n){
if (!n) return 0;
if (!n.left) return 1 + minDepth(n.right);
if (!n.right) return 1 + minDepth(n.left);
return 1 + Math.min(minDepth(n.left), minDepth(n.right));
}Tradeoff:
2. BFS level order
Return depth on first leaf encountered.
- Time
- O(n)
- Space
- O(w)
function minDepthBFS(root) {
if (!root) return 0;
const q = [[root, 1]];
while (q.length) {
const [n, d] = q.shift();
if (!n.left && !n.right) return d;
if (n.left) q.push([n.left, d+1]);
if (n.right) q.push([n.right, d+1]);
}
}Tradeoff:
Tesla-specific tips
Tesla prefers BFS for shortest-path-style problems — same shape as the breadth-first frontier used in real-time graph planning where you want the first viable trajectory, not the deepest.
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