146. LRU Cache
mediumAsked at AMDDesign a Least Recently Used cache with O(1) get and put. AMD asks this because cache design is central to their business — TLBs, L1/L2/L3 caches, and GPU shared-memory eviction policies all operate on LRU or LRU-like principles. Understanding the data structure composition here directly maps to hardware cache architecture reasoning.
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Source citations
Public interview reports confirming this problem appears in AMD loops.
- Glassdoor (2026-Q1)— AMD SWE candidates consistently cite LRU Cache as a high-frequency medium at AMD, often accompanied by hardware cache follow-ups.
- Blind (2025-11)— AMD interview threads flag LRU Cache as the canonical data-structure-composition problem for AMD's hardware-aware engineering culture.
Problem
Design a data structure that follows the constraints of a Least Recently Used (LRU) cache. Implement the LRUCache class: LRUCache(capacity) initializes the LRU cache with a positive size capacity. int get(int key) returns the value of the key if it exists, otherwise -1. void put(int key, int value) updates the value if the key exists, otherwise inserts the key-value pair. When the number of keys exceeds the capacity, evict the least recently used key. Both get and put must run in O(1) average time complexity.
Constraints
1 <= capacity <= 30000 <= key <= 10^40 <= value <= 10^5At most 2 * 10^5 calls will be made to get and put.
Examples
Example 1
LRUCache(2); put(1,1); put(2,2); get(1); put(3,3); get(2); put(4,4); get(1); get(3); get(4)[null,null,null,1,null,-1,null,1,3,4]Explanation: After put(3,3), key 2 (least recently used) is evicted. After put(4,4), key 1 was used by get(1), so key 3 is evicted instead.
Approaches
1. Ordered Map (JS Map insertion order)
JS Map preserves insertion order. On access, delete and re-insert to move to the end (most recent). Evict the first key (least recent) when over capacity.
- Time
- O(1) get and put
- Space
- O(capacity)
class LRUCache {
constructor(capacity) {
this.capacity = capacity;
this.cache = new Map();
}
get(key) {
if (!this.cache.has(key)) return -1;
const val = this.cache.get(key);
this.cache.delete(key);
this.cache.set(key, val);
return val;
}
put(key, value) {
if (this.cache.has(key)) this.cache.delete(key);
this.cache.set(key, value);
if (this.cache.size > this.capacity) {
this.cache.delete(this.cache.keys().next().value);
}
}
}Tradeoff: O(1) amortized. Relies on JS Map's insertion-order guarantee (ECMAScript spec). Practical for JS. AMD interviewers will typically ask for the explicit doubly-linked-list version to confirm understanding.
2. Hash Map + Doubly Linked List (canonical)
A Map provides O(1) key lookup; a doubly-linked list provides O(1) move-to-front and evict-from-tail. The map stores key → node. Dummy head and tail sentinels eliminate edge cases.
- Time
- O(1) get and put
- Space
- O(capacity)
class Node {
constructor(key, val) { this.key = key; this.val = val; this.prev = this.next = null; }
}
class LRUCache {
constructor(capacity) {
this.capacity = capacity;
this.map = new Map();
this.head = new Node(0, 0); // dummy MRU end
this.tail = new Node(0, 0); // dummy LRU end
this.head.next = this.tail;
this.tail.prev = this.head;
}
_remove(node) {
node.prev.next = node.next;
node.next.prev = node.prev;
}
_insertFront(node) {
node.next = this.head.next;
node.prev = this.head;
this.head.next.prev = node;
this.head.next = node;
}
get(key) {
if (!this.map.has(key)) return -1;
const node = this.map.get(key);
this._remove(node);
this._insertFront(node);
return node.val;
}
put(key, value) {
if (this.map.has(key)) this._remove(this.map.get(key));
const node = new Node(key, value);
this._insertFront(node);
this.map.set(key, node);
if (this.map.size > this.capacity) {
const lru = this.tail.prev;
this._remove(lru);
this.map.delete(lru.key);
}
}
}Tradeoff: True O(1) for all operations. No reliance on language insertion-order behavior. This is the answer AMD expects for a hardware-aware role.
AMD-specific tips
AMD's entire product line revolves around cache design: CPU L1/L2/L3, GPU shared memory, TLBs, texture caches, and PCIe buffer caches all use LRU or pseudo-LRU eviction. Frame your answer architecturally before writing code: 'O(1) lookup needs a hash map; O(1) move-to-front and O(1) eviction from the tail need a doubly-linked list — a singly-linked list can't remove a node in O(1) without its predecessor.' AMD interviewers will probe how hardware LRU differs from this software version — mention that hardware uses pseudo-LRU trees for associativity constraints.
Common mistakes
- Using a singly-linked list — removing an arbitrary node requires O(n) traversal.
- Forgetting to remove the evicted node from the map — the map and DLL must stay in sync.
- Not moving the node to the front on get() — a cache hit makes the entry most-recently-used.
- Skipping dummy head/tail — every insert/remove then requires null-checks for the first and last node.
Follow-up questions
An interviewer at AMD may pivot to one of these next:
- LFU Cache (LC 460) — evict the least-frequently-used entry; requires a frequency-bucket DLL.
- How does hardware pseudo-LRU differ from true LRU in a set-associative cache?
- What is the time complexity if you implemented this with a sorted array instead?
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FAQ
Why a doubly-linked list and not a singly-linked list?
To remove an arbitrary node in O(1), you need a pointer to its predecessor. A singly-linked list requires O(n) traversal to find the predecessor.
Why dummy sentinel nodes?
They eliminate null checks at the head and tail. Every insert and remove is uniform pointer rewiring — no special cases for empty list or single-element list.
How does pseudo-LRU differ from this software LRU?
Hardware caches have fixed associativity (e.g., 8-way). Tracking true LRU order for 8 slots needs 3 bits per way. Pseudo-LRU approximates this with a binary tree of bits, sacrificing perfect LRU for simpler hardware implementation.
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