2. Valid Parentheses
easyAsked at AutodeskDetermine if a string of brackets is properly opened and closed.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a string containing the characters '()', '[]', and '{}', determine if the input string is valid. Brackets must close in the correct order and every opener must have a matching closer of the same type.
Constraints
1 <= s.length <= 10^4s consists of bracket characters only
Examples
Example 1
s="()[]{}"trueExample 2
s="(]"falseApproaches
1. Brute force replace
Repeatedly strip matched pairs until no change.
- Time
- O(n^2)
- Space
- O(n)
while (s.includes('()') || s.includes('[]') || s.includes('{}'))
s = s.replace('()','').replace('[]','').replace('{}','');
return s.length===0;Tradeoff:
2. Stack
Push openers and pop on closers, verifying the match. Empty stack at the end means valid.
- Time
- O(n)
- Space
- O(n)
function isValid(s) {
const map = { ')':'(', ']':'[', '}':'{' };
const stack = [];
for (const c of s) {
if (!map[c]) stack.push(c);
else if (stack.pop() !== map[c]) return false;
}
return stack.length === 0;
}Tradeoff:
Autodesk-specific tips
Autodesk uses stacks heavily for undo history in DWG/Revit edits, so this maps directly to their command-pattern expectations.
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