4. Best Time to Buy and Sell Stock
easyAsked at AutodeskFind the max profit from one buy-and-sell of a stock given daily prices.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
You are given an array prices where prices[i] is the price of a given stock on day i. Return the maximum profit you can achieve by choosing a single day to buy and a later day to sell. Return 0 if no profit is possible.
Constraints
1 <= prices.length <= 10^50 <= prices[i] <= 10^4
Examples
Example 1
prices=[7,1,5,3,6,4]5Example 2
prices=[7,6,4,3,1]0Approaches
1. Brute force pairs
Try every (buy, sell) pair and track the max gain.
- Time
- O(n^2)
- Space
- O(1)
let best=0;
for (let i=0;i<prices.length;i++)
for (let j=i+1;j<prices.length;j++)
best=Math.max(best, prices[j]-prices[i]);
return best;Tradeoff:
2. Running minimum
Track the minimum price seen so far and compare each new price against it for max profit. One linear pass.
- Time
- O(n)
- Space
- O(1)
function maxProfit(prices) {
let minPrice = Infinity;
let best = 0;
for (const p of prices) {
if (p < minPrice) minPrice = p;
else if (p - minPrice > best) best = p - minPrice;
}
return best;
}Tradeoff:
Autodesk-specific tips
Autodesk likes single-pass min/max trackers because the same shape powers bounding-box reductions and ray casting min-t computations.
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