11. Add Two Numbers
mediumAsked at ByteDanceAdd two non-negative integers stored as reverse-order linked lists — ByteDance uses it to test edge-case pointer handling before deeper feed-pipeline questions.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given two non-empty linked lists representing non-negative integers in reverse order, where each node holds a single digit, return the sum as a linked list in the same reverse order.
Constraints
1 <= each list length <= 1000 <= Node.val <= 9No leading zeros except the number 0 itself
Examples
Example 1
l1 = [2,4,3], l2 = [5,6,4][7,0,8]Example 2
l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9][8,9,9,9,0,0,0,1]Approaches
1. Convert to bigint and back
Walk both lists into strings, sum as BigInt, then rebuild a list.
- Time
- O(n)
- Space
- O(n)
// build numbers from digits, sum, then walk digits back into nodesTradeoff:
2. Simulate column addition with carry
Walk both lists in lockstep summing digits plus a carry, producing one node per column. Handles unequal lengths naturally.
- Time
- O(max(m, n))
- Space
- O(max(m, n))
function addTwoNumbers(l1, l2) {
const dummy = { val: 0, next: null };
let cur = dummy, carry = 0;
while (l1 || l2 || carry) {
const a = l1 ? l1.val : 0;
const b = l2 ? l2.val : 0;
const s = a + b + carry;
carry = Math.floor(s / 10);
cur.next = { val: s % 10, next: null };
cur = cur.next;
if (l1) l1 = l1.next;
if (l2) l2 = l2.next;
}
return dummy.next;
}Tradeoff:
ByteDance-specific tips
ByteDance interviewers expect the trailing-carry case called out before code, matching how their feed-aggregation team plans overflow handling up front.
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