4. Best Time to Buy and Sell Stock
easyAsked at ByteDanceFind the maximum profit from a single buy-sell pair — ByteDance uses it to test running-minimum bookkeeping before scaling to streaming ranking signals.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an array prices where prices[i] is the price of a stock on day i, return the maximum profit you can achieve from buying on one day and selling on a later day. Return 0 if no profit is possible.
Constraints
1 <= prices.length <= 10^50 <= prices[i] <= 10^4
Examples
Example 1
prices = [7,1,5,3,6,4]5Example 2
prices = [7,6,4,3,1]0Approaches
1. Brute force
Check every pair (i, j) with j > i.
- Time
- O(n^2)
- Space
- O(1)
let best = 0;
for (let i=0;i<p.length;i++)
for (let j=i+1;j<p.length;j++)
best = Math.max(best, p[j]-p[i]);Tradeoff:
2. Running minimum
Track the lowest price seen so far; the best profit is the max gap from that minimum to today's price.
- Time
- O(n)
- Space
- O(1)
function maxProfit(prices) {
let lo = Infinity, best = 0;
for (const p of prices) {
lo = Math.min(lo, p);
best = Math.max(best, p - lo);
}
return best;
}Tradeoff:
ByteDance-specific tips
ByteDance values the framing that this is a streaming-min problem, which mirrors how their recommendation system tracks running engagement minima across watch sessions.
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