8. Merge Sorted Array
easyAsked at DigitalOceanMerge two sorted arrays in-place into the first one — DigitalOcean uses this to test two-pointer fluency that maps to merging per-region usage windows into one billing batch.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given two sorted arrays nums1 of length m+n with m valid elements and nums2 of length n, merge nums2 into nums1 as one sorted array in-place. Use the trailing n empty slots in nums1.
Constraints
nums1.length == m+nnums2.length == n0 <= m, n <= 200Both inputs sorted non-decreasing
Examples
Example 1
nums1=[1,2,3,0,0,0], m=3, nums2=[2,5,6], n=3[1,2,2,3,5,6]Example 2
nums1=[1], m=1, nums2=[], n=0[1]Approaches
1. Concat and sort
Overwrite tail with nums2, then sort the whole array.
- Time
- O((m+n) log(m+n))
- Space
- O(1)
for (let i = 0; i < n; i++) nums1[m+i] = nums2[i];
nums1.sort((a,b)=>a-b);Tradeoff:
2. Backwards two-pointer
Fill nums1 from the tail using the larger of the two pointers. No shifting needed.
- Time
- O(m+n)
- Space
- O(1)
function merge(nums1, m, nums2, n) {
let i = m - 1, j = n - 1, k = m + n - 1;
while (j >= 0) {
if (i >= 0 && nums1[i] > nums2[j]) nums1[k--] = nums1[i--];
else nums1[k--] = nums2[j--];
}
}Tradeoff:
DigitalOcean-specific tips
DigitalOcean grades the tail-walk solution highly because it avoids the destructive sort that would re-touch all m+n entries during high-volume usage merges.
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