22. Word Break
mediumAsked at GrabDecide whether a string can be segmented into dictionary words — Grab uses this as a DP-on-strings warm-up.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a string s and a dictionary of strings wordDict, return true if s can be segmented into a space-separated sequence of one or more dictionary words.
Constraints
1 <= s.length <= 3001 <= wordDict.length <= 10001 <= wordDict[i].length <= 20
Examples
Example 1
s = "leetcode", wordDict = ["leet","code"]trueExample 2
s = "catsandog", wordDict = ["cats","dog","sand","and","cat"]falseApproaches
1. Plain recursion
Try every dictionary word as a prefix; recurse on the suffix.
- Time
- O(2^n)
- Space
- O(n)
function can(s) {
if (s === '') return true;
for (const w of wordDict)
if (s.startsWith(w) && can(s.slice(w.length))) return true;
return false;
}Tradeoff:
2. Bottom-up DP
dp[i] = true if s[0..i] is segmentable; fill left-to-right by checking each ending split.
- Time
- O(n^2 * k)
- Space
- O(n)
function wordBreak(s, wordDict) {
const set = new Set(wordDict);
const dp = new Array(s.length + 1).fill(false);
dp[0] = true;
for (let i = 1; i <= s.length; i++) {
for (let j = 0; j < i; j++) {
if (dp[j] && set.has(s.slice(j, i))) { dp[i] = true; break; }
}
}
return dp[s.length];
}Tradeoff:
Grab-specific tips
Grab interviewers expect you to memoize from the start — frame as parsing concatenated SEA service codes (food + ride + wallet) into known prefixes.
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