3. Merge Two Sorted Lists
easyAsked at GrabMerge two sorted linked lists into one — a Grab favorite for testing pointer hygiene.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given the heads of two sorted linked lists, splice them together by reusing nodes from the two input lists and return the head of the new merged sorted list.
Constraints
0 <= total nodes <= 50-100 <= Node.val <= 100Both lists sorted non-decreasing
Examples
Example 1
l1 = [1,2,4], l2 = [1,3,4][1,1,2,3,4,4]Example 2
l1 = [], l2 = [0][0]Approaches
1. Collect and sort
Extract values into an array, sort, rebuild.
- Time
- O(n log n)
- Space
- O(n)
const arr = [];
while (l1) { arr.push(l1.val); l1 = l1.next; }
while (l2) { arr.push(l2.val); l2 = l2.next; }
arr.sort((a,b) => a-b);Tradeoff:
2. Two-pointer splice
Walk both lists with a dummy head, attaching the smaller node each step.
- Time
- O(n + m)
- Space
- O(1)
function mergeTwoLists(l1, l2) {
const dummy = { next: null };
let tail = dummy;
while (l1 && l2) {
if (l1.val <= l2.val) { tail.next = l1; l1 = l1.next; }
else { tail.next = l2; l2 = l2.next; }
tail = tail.next;
}
tail.next = l1 || l2;
return dummy.next;
}Tradeoff:
Grab-specific tips
Grab phones often follow up with 'merge K sorted streams' to map to their order-pipeline architecture — say it explicitly to score signal.
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