17. Best Time to Buy and Sell Stock
easyAsked at RedditFind the max profit from one buy + one sell of a stock-price array. Reddit uses this as a streaming-window template — the same single-pass shape used to find the best upvote burst within a post's lifetime.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Source citations
Public interview reports confirming this problem appears in Reddit loops.
- Glassdoor (2026-Q1)— Reddit data-platform phone screen.
- LeetCode Discuss (2025-10)— Reported as a common warmup for ranking/streaming questions.
Problem
You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock. Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
Constraints
1 <= prices.length <= 10^50 <= prices[i] <= 10^4
Examples
Example 1
prices = [7,1,5,3,6,4]5Explanation: Buy on day 2 (price=1), sell on day 5 (price=6).
Example 2
prices = [7,6,4,3,1]0Explanation: No profitable trade exists.
Approaches
1. All pairs
Nested loop: for every (buy, sell), compute profit.
- Time
- O(n^2)
- Space
- O(1)
function maxProfit(prices) {
let best = 0;
for (let i = 0; i < prices.length; i++) {
for (let j = i + 1; j < prices.length; j++) {
best = Math.max(best, prices[j] - prices[i]);
}
}
return best;
}Tradeoff: Quadratic. TLE for 10^5 input.
2. Single-pass min-so-far (optimal)
Track the lowest price seen so far. At each day, candidate profit = today's price - min so far.
- Time
- O(n)
- Space
- O(1)
function maxProfit(prices) {
let minPrice = Infinity;
let best = 0;
for (const p of prices) {
if (p < minPrice) minPrice = p;
else if (p - minPrice > best) best = p - minPrice;
}
return best;
}Tradeoff: One pass, O(1) memory. Reddit's hot-burst detector uses the same min-tracker over a windowed timeline.
Reddit-specific tips
Reddit interviewers grade on the invariant: 'at every step, the best profit so far assumes we sold today.' Bonus signal: relate this to their hot-score logic — track the minimum upvote count in a window, then find the best upvote burst since.
Common mistakes
- Returning a negative profit instead of 0 (must clamp).
- Initializing best to -Infinity (the problem says return 0 if no profit).
- Using two separate passes when one suffices.
Follow-up questions
An interviewer at Reddit may pivot to one of these next:
- II (LC 122): multiple transactions — greedy sum of positive deltas.
- III (LC 123): exactly 2 transactions — DP.
- IV (LC 188): at most k transactions — DP.
Solve it now
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FAQ
Why does this not need DP?
There's only one transaction; the best 'buy' is always the running minimum. DP becomes necessary when k > 1.
Does the buy-sell constraint matter?
Yes — sell must be strictly after buy. The single-pass naturally enforces this because we only consider sells after a buy candidate.
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