14. Minimum Depth of Binary Tree
easyAsked at SlackFind the depth of the nearest leaf in a binary tree.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given the root of a binary tree, find its minimum depth — the number of nodes along the shortest path from root down to the nearest leaf node.
Constraints
Nodes count in [0, 10^5]-1000 <= Node.val <= 1000
Examples
Example 1
root = [3,9,20,null,null,15,7]2Example 2
root = [2,null,3,null,4,null,5,null,6]5Approaches
1. DFS all paths
DFS every root-to-leaf path, track minimum.
- Time
- O(n)
- Space
- O(h)
let best = Infinity;
function dfs(n,d){ if(!n) return; if(!n.left&&!n.right) best=Math.min(best,d); dfs(n.left,d+1); dfs(n.right,d+1);}
dfs(root,1);
return root? best : 0;Tradeoff:
2. BFS
Level-order traversal returns the depth of the first leaf encountered, which is the minimum.
- Time
- O(n)
- Space
- O(w)
function minDepth(root) {
if (!root) return 0;
const q = [[root, 1]];
while (q.length) {
const [n, d] = q.shift();
if (!n.left && !n.right) return d;
if (n.left) q.push([n.left, d + 1]);
if (n.right) q.push([n.right, d + 1]);
}
}Tradeoff:
Slack-specific tips
Slack interviewers prefer BFS for min-depth because it short-circuits — DFS forces you to explore every leaf, which they'll call out.
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