5. Remove Element
easyAsked at SlackRemove all occurrences of val from an array in place and return the new length.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an integer array nums and an integer val, remove all occurrences of val in nums in-place. Return the number of elements that remain; the order of the kept elements may be changed.
Constraints
0 <= nums.length <= 1000 <= nums[i], val <= 50
Examples
Example 1
nums = [3,2,2,3], val = 32, nums = [2,2,_,_]Example 2
nums = [0,1,2,2,3,0,4,2], val = 25, nums = [0,1,4,0,3,_,_,_]Approaches
1. Filter copy
Filter array, then copy back.
- Time
- O(n)
- Space
- O(n)
const kept = nums.filter(x=>x!==val);
for (let i=0;i<kept.length;i++) nums[i]=kept[i];
return kept.length;Tradeoff:
2. Two pointers
Walk fast pointer; copy to slow pointer when value differs from val.
- Time
- O(n)
- Space
- O(1)
function removeElement(nums, val) {
let slow = 0;
for (let fast = 0; fast < nums.length; fast++) {
if (nums[fast] !== val) {
nums[slow] = nums[fast];
slow++;
}
}
return slow;
}Tradeoff:
Slack-specific tips
Slack engineers will probe whether you preserve order; mention the swap-with-last optimization for unordered removals (mute-list cleanup).
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