5. Remove Element
easyAsked at BrexRemove all occurrences of a value in-place from an array and return the new length.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an array nums and an integer val, remove all occurrences of val in nums in-place. The order of the remaining elements may be changed. Return the number of remaining elements.
Constraints
0 <= nums.length <= 1000 <= nums[i] <= 500 <= val <= 100
Examples
Example 1
nums = [3,2,2,3], val = 32, nums=[2,2,_,_]Example 2
nums = [0,1,2,2,3,0,4,2], val = 25, nums=[0,1,3,0,4,_,_,_]Approaches
1. Brute force filter
Build a new array filtered by val and copy back.
- Time
- O(n)
- Space
- O(n)
const out=nums.filter(x=>x!==val);
for(let i=0;i<out.length;i++) nums[i]=out[i];
return out.length;Tradeoff:
2. Two pointers
Write pointer only advances on non-val. Single linear pass, no extra memory.
- Time
- O(n)
- Space
- O(1)
function removeElement(nums, val) {
let k = 0;
for (let i = 0; i < nums.length; i++) {
if (nums[i] !== val) {
nums[k] = nums[i];
k++;
}
}
return k;
}Tradeoff:
Brex-specific tips
Brex interviewers like to follow this up with a question on filtering reversed or disputed transactions from a card-event array, so be ready to discuss why the relative order of survivors may or may not matter.
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