5. Remove Element
easyAsked at ChimeRemove all occurrences of a value in-place from an array and return the new length.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an integer array nums and an integer val, remove all occurrences of val in-place. The relative order may change. Return the number of elements that are not equal to val.
Constraints
0 <= nums.length <= 1000 <= nums[i], val <= 50
Examples
Example 1
nums = [3,2,2,3], val = 32, nums = [2,2,_,_]Example 2
nums = [0,1,2,2,3,0,4,2], val = 25, nums = [0,1,4,0,3,_,_,_]Approaches
1. Filter to new array
Build a new array excluding val and copy back.
- Time
- O(n)
- Space
- O(n)
const out = nums.filter(x => x !== val);
for (let i = 0; i < out.length; i++) nums[i] = out[i];
return out.length;Tradeoff:
2. Two-pointer write index
Slow write pointer advances only when value is kept.
- Time
- O(n)
- Space
- O(1)
function removeElement(nums, val) {
let k = 0;
for (let i = 0; i < nums.length; i++) {
if (nums[i] !== val) nums[k++] = nums[i];
}
return k;
}Tradeoff:
Chime-specific tips
Chime regularly filters fraudulent or reversed transactions out of in-memory ledgers; demonstrate that you can mutate arrays in place without extra allocation.
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