3. Merge Two Sorted Lists
easyAsked at BrexMerge two sorted linked lists into one sorted list by splicing nodes together.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
You are given the heads of two sorted linked lists list1 and list2. Merge the two lists into one sorted list by splicing together the nodes of the first two lists. Return the head of the merged list.
Constraints
0 <= list length <= 50-100 <= node value <= 100Both lists sorted ascending
Examples
Example 1
list1 = [1,2,4], list2 = [1,3,4][1,1,2,3,4,4]Example 2
list1 = [], list2 = [][]Approaches
1. Brute force collect
Copy both lists into an array, sort, rebuild list.
- Time
- O((n+m) log(n+m))
- Space
- O(n+m)
const arr=[]; while(l1){arr.push(l1.val);l1=l1.next;}
while(l2){arr.push(l2.val);l2=l2.next;}
arr.sort((a,b)=>a-b);Tradeoff:
2. Iterative two-pointer splice
Walk both heads with a dummy node, attach the smaller each step. Linear and in-place.
- Time
- O(n+m)
- Space
- O(1)
function mergeTwoLists(l1, l2) {
const dummy = { next: null };
let tail = dummy;
while (l1 && l2) {
if (l1.val <= l2.val) { tail.next = l1; l1 = l1.next; }
else { tail.next = l2; l2 = l2.next; }
tail = tail.next;
}
tail.next = l1 || l2;
return dummy.next;
}Tradeoff:
Brex-specific tips
At Brex, merging sorted lists shows up as combining authorized and settled transaction streams, so call out preserving timestamp order and handling concurrent ingest of card events.
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