5. Remove Element
easyAsked at UdemyStrip occurrences of a value in place — Udemy uses this to test pointer mechanics before harder catalog-cleanup problems.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an array nums and an integer val, remove all occurrences of val in place and return the new length k. The first k elements of nums may be in any order.
Constraints
0 <= nums.length <= 1000 <= nums[i], val <= 50
Examples
Example 1
nums=[3,2,2,3], val=32, nums=[2,2,_,_]Example 2
nums=[0,1,2,2,3,0,4,2], val=25, nums=[0,1,3,0,4,_,_,_]Approaches
1. Filter and copy
Filter non-val into a new array, then copy back.
- Time
- O(n)
- Space
- O(n)
const keep = nums.filter(x => x !== val);
for (let i = 0; i < keep.length; i++) nums[i] = keep[i];
return keep.length;Tradeoff:
2. Two-pointer in place
Use a write pointer; advance read pointer and copy forward only when nums[i] !== val.
- Time
- O(n)
- Space
- O(1)
function removeElement(nums, val) {
let k = 0;
for (let i = 0; i < nums.length; i++) {
if (nums[i] !== val) nums[k++] = nums[i];
}
return k;
}Tradeoff:
Udemy-specific tips
Udemy may reframe this as scrubbing flagged-review entries from a course rating list — show you keep the pattern simple and don't allocate copies.
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