4. Remove Duplicates from Sorted Array
easyAsked at GoDaddyRemove duplicates from a sorted array in-place and return the new length.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a sorted array nums, remove the duplicates in-place such that each unique element appears only once. Return the number of unique elements, with the first k positions of nums holding them in order.
Constraints
1 <= nums.length <= 3*10^4-100 <= nums[i] <= 100nums sorted non-decreasing
Examples
Example 1
nums = [1,1,2]2, nums = [1,2,_]Example 2
nums = [0,0,1,1,1,2,2,3,3,4]5, nums = [0,1,2,3,4,...]Approaches
1. Set then copy
Use a Set to dedupe, then write back into nums.
- Time
- O(n)
- Space
- O(n)
const u=[...new Set(nums)]; for(let i=0;i<u.length;i++) nums[i]=u[i]; return u.length;Tradeoff:
2. Two pointer in-place
Slow pointer marks last unique; fast scans and writes new uniques.
- Time
- O(n)
- Space
- O(1)
function removeDuplicates(nums) {
if (nums.length === 0) return 0;
let slow = 0;
for (let fast = 1; fast < nums.length; fast++) {
if (nums[fast] !== nums[slow]) {
slow++;
nums[slow] = nums[fast];
}
}
return slow + 1;
}Tradeoff:
GoDaddy-specific tips
GoDaddy uses this to test whether candidates can dedupe domain-name lists (e.g., suggested alternates) in-place without re-allocating large arrays.
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