24. Subarray Sum Equals K
mediumAsked at TeslaCount subarrays whose values sum to a target — Tesla uses prefix-sum anomaly detection on vehicle telemetry streams to count windows where cumulative sensor drift exceeds a threshold, triggering a recalibration event in the sensor fusion pipeline.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an integer array nums and an integer k, return the total number of contiguous subarrays whose sum equals k.
Constraints
1 <= nums.length <= 2 * 10^4-1000 <= nums[i] <= 1000-10^7 <= k <= 10^7
Examples
Example 1
nums = [1,1,1], k = 22Explanation: Subarrays [1,1] (indices 0-1) and [1,1] (indices 1-2) both sum to 2.
Example 2
nums = [1,2,3], k = 32Approaches
1. Brute force O(n^2)
For every pair (i, j), compute the subarray sum and check if it equals k. No extra space, but quadratic time.
- Time
- O(n^2)
- Space
- O(1)
function subarraySum(nums, k) {
let count = 0;
for (let i = 0; i < nums.length; i++) {
let sum = 0;
for (let j = i; j < nums.length; j++) {
sum += nums[j];
if (sum === k) count++;
}
}
return count;
}Tradeoff:
2. Prefix sum with hash map
Store frequency of prefix sums seen so far. For each position, check how many previous prefix sums equal currentSum - k. Single pass, O(n).
- Time
- O(n)
- Space
- O(n)
function subarraySum(nums, k) {
const prefixCount = new Map([[0, 1]]);
let sum = 0, count = 0;
for (const num of nums) {
sum += num;
count += prefixCount.get(sum - k) || 0;
prefixCount.set(sum, (prefixCount.get(sum) || 0) + 1);
}
return count;
}Tradeoff:
Tesla-specific tips
Tesla uses continuous sensor data — gyroscope, accelerometer, radar — and needs to detect anomaly windows efficiently in real time. The prefix-sum trick is the key insight; many candidates never arrive at it without a nudge. Practice explaining it without jargon: 'If the sum from 0 to j equals k + sum from 0 to i, then the subarray from i+1 to j sums to k.' Note that sliding window does NOT work here because negative values break the monotonic-sum assumption — say that proactively.
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