16. Longest Substring Without Repeating Characters
mediumAsked at YelpFind the length of the longest substring with all distinct characters — Yelp uses this sliding-window pattern to test whether candidates can scale to deduping review n-grams.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a string s, find the length of the longest substring without repeating characters. Substrings must be contiguous.
Constraints
0 <= s.length <= 5 * 10^4s consists of English letters, digits, symbols and spaces
Examples
Example 1
s = "abcabcbb"3Example 2
s = "bbbbb"1Approaches
1. Brute force
Check every substring for distinct characters.
- Time
- O(n^3)
- Space
- O(min(n, k))
let best = 0;
for (let i = 0; i < s.length; i++)
for (let j = i; j < s.length; j++) {
const sub = s.slice(i, j+1);
if (new Set(sub).size === sub.length) best = Math.max(best, sub.length);
}
return best;Tradeoff:
2. Sliding window with last-seen map
Track the last index where each character appeared and jump the left pointer past any repeat.
- Time
- O(n)
- Space
- O(k)
function lengthOfLongestSubstring(s) {
const last = new Map();
let l = 0, best = 0;
for (let r = 0; r < s.length; r++) {
if (last.has(s[r]) && last.get(s[r]) >= l) l = last.get(s[r]) + 1;
last.set(s[r], r);
best = Math.max(best, r - l + 1);
}
return best;
}Tradeoff:
Yelp-specific tips
Yelp will pivot to review fraud — be ready to discuss how a sliding-window dedup window flags reviews where the same phrase repeats across submissions from the same IP block.
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