3. Merge Two Sorted Lists
easyAsked at ZoomMerge two sorted linked lists into one sorted list.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
You are given the heads of two sorted linked lists list1 and list2. Splice the nodes together into one sorted list and return its head.
Constraints
0 <= count <= 50 per list-100 <= Node.val <= 100Both lists are sorted non-decreasing
Examples
Example 1
l1=[1,2,4], l2=[1,3,4][1,1,2,3,4,4]Example 2
l1=[], l2=[0][0]Approaches
1. Copy to array and sort
Collect values, sort, rebuild list.
- Time
- O((n+m) log(n+m))
- Space
- O(n+m)
const v=[]; while(l1){v.push(l1.val);l1=l1.next} while(l2){v.push(l2.val);l2=l2.next}
v.sort((a,b)=>a-b); return buildList(v);Tradeoff:
2. Two-pointer splice
Walk both heads with a tail pointer and stitch the smaller node next. No extra allocation.
- Time
- O(n+m)
- Space
- O(1)
function merge(l1, l2) {
const dummy = { next: null };
let tail = dummy;
while (l1 && l2) {
if (l1.val <= l2.val) { tail.next = l1; l1 = l1.next; }
else { tail.next = l2; l2 = l2.next; }
tail = tail.next;
}
tail.next = l1 || l2;
return dummy.next;
}Tradeoff:
Zoom-specific tips
Zoom often uses merged-list problems as a warmup before merging time-ordered participant event streams (joins, leaves, mute toggles) — call out that connection.
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