8. Merge Sorted Array
easyAsked at Electronic ArtsMerge nums2 into nums1 in place, exploiting trailing zero slots and walking from the back.
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Problem
nums1 has length m+n with the first m valid slots and n trailing zeros; nums2 has n sorted values. Merge nums2 into nums1 in place so that nums1 is fully sorted.
Constraints
nums1.length == m + nnums2.length == n0 <= m, n <= 200
Examples
Example 1
nums1=[1,2,3,0,0,0], m=3, nums2=[2,5,6], n=3[1,2,2,3,5,6]Example 2
nums1=[1], m=1, nums2=[], n=0[1]Approaches
1. Append and sort
Copy nums2 into nums1's tail, then sort.
- Time
- O((m+n) log(m+n))
- Space
- O(1)
for(let i=0;i<n;i++) nums1[m+i]=nums2[i];
nums1.sort((a,b)=>a-b);Tradeoff:
2. Three pointers from the back
Place the larger of nums1[i] and nums2[j] at the end and decrement; no element is overwritten before being read.
- Time
- O(m+n)
- Space
- O(1)
function merge(nums1, m, nums2, n) {
let i = m - 1, j = n - 1, k = m + n - 1;
while (j >= 0) {
if (i >= 0 && nums1[i] > nums2[j]) nums1[k--] = nums1[i--];
else nums1[k--] = nums2[j--];
}
}Tradeoff:
Electronic Arts-specific tips
EA tooling teams deal with in-place merges of replay-event buffers, so the from-the-back pointer trick is the canonical answer they want to see.
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