22. Minimum Path Sum
mediumAsked at Electronic ArtsFind the minimum cost path from top-left to bottom-right of a grid using DP, mirroring EA's movement cost and terrain-weight calculations in strategy game pathfinding.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an m x n grid filled with non-negative numbers, find a path from the top-left to the bottom-right corner which minimizes the sum of all numbers along its path. You can only move either down or right at any point in time.
Constraints
m == grid.length, n == grid[i].length1 <= m, n <= 2000 <= grid[i][j] <= 200
Examples
Example 1
grid = [[1,3,1],[1,5,1],[4,2,1]]7Example 2
grid = [[1,2,3],[4,5,6]]12Approaches
1. Recursive with memoization
Recurse from bottom-right, memoize subproblem results to avoid recomputation.
- Time
- O(m*n)
- Space
- O(m*n)
function minPathSum(grid) {
const m = grid.length, n = grid[0].length;
const memo = {};
function dp(r, c) {
if (r === m-1 && c === n-1) return grid[r][c];
if (r >= m || c >= n) return Infinity;
const key = r+','+c;
if (memo[key] !== undefined) return memo[key];
memo[key] = grid[r][c] + Math.min(dp(r+1,c), dp(r,c+1));
return memo[key];
}
return dp(0, 0);
}Tradeoff:
2. Bottom-up DP in-place
Modify the grid in-place: each cell accumulates the minimum cost to reach it from top-left. No extra space needed, and EA interviewers appreciate the O(1) extra space technique for map-cost DP.
- Time
- O(m*n)
- Space
- O(1)
function minPathSum(grid) {
const m = grid.length, n = grid[0].length;
for (let r = 0; r < m; r++) {
for (let c = 0; c < n; c++) {
if (r === 0 && c === 0) continue;
const up = r > 0 ? grid[r-1][c] : Infinity;
const left = c > 0 ? grid[r][c-1] : Infinity;
grid[r][c] += Math.min(up, left);
}
}
return grid[m-1][n-1];
}Tradeoff:
Electronic Arts-specific tips
EA interviews cover game development data structures, pathfinding (A*, BFS on grids), spatial algorithms, and simulation problems. Grid/matrix manipulation and BFS on 2D arrays are very common.
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