9. Single Number
easyAsked at KlarnaFind the one element that appears exactly once in an array where every other element appears twice.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given a non-empty array of integers where every element appears twice except for one, find that single one. Your solution must run in linear time and use constant extra space.
Constraints
1 <= nums.length <= 3 * 10^4Exactly one element appears once; all others appear twice
Examples
Example 1
nums = [2,2,1]1Example 2
nums = [4,1,2,1,2]4Approaches
1. Hash map count
Count occurrences in a map, then scan for count==1.
- Time
- O(n)
- Space
- O(n)
function singleNumber(nums) {
const c = new Map();
for (const n of nums) c.set(n, (c.get(n) || 0) + 1);
for (const [k, v] of c) if (v === 1) return k;
}Tradeoff:
2. XOR fold
Pairs cancel under XOR, so XOR-folding the whole array leaves only the unique value. Constant space.
- Time
- O(n)
- Space
- O(1)
function singleNumber(nums) {
let x = 0;
for (const n of nums) x ^= n;
return x;
}Tradeoff:
Klarna-specific tips
Klarna risk-feature engineers grade this on whether you reach for the XOR trick fast; they reuse it for parity checks across replicated installment-ledger shards.
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