13. Maximum Depth of Binary Tree
easyAsked at UdemyFind the maximum depth of a binary tree — Udemy uses this to probe recursive DFS fundamentals before asking about course-category tree traversals.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given the root of a binary tree, return its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Constraints
0 <= number of nodes <= 10^4-100 <= Node.val <= 100
Examples
Example 1
root = [3,9,20,null,null,15,7]3Example 2
root = [1,null,2]2Approaches
1. Brute force BFS
Level-order traversal counting each level.
- Time
- O(n)
- Space
- O(n)
function maxDepth(root) {
if (!root) return 0;
let depth = 0;
const queue = [root];
while (queue.length) {
depth++;
const size = queue.length;
for (let i = 0; i < size; i++) {
const node = queue.shift();
if (node.left) queue.push(node.left);
if (node.right) queue.push(node.right);
}
}
return depth;
}Tradeoff:
2. Recursive DFS
Return 1 + max of left and right subtree depths; base case returns 0 for null. Single-line elegance preferred by Udemy interviewers.
- Time
- O(n)
- Space
- O(h)
function maxDepth(root) {
if (!root) return 0;
return 1 + Math.max(maxDepth(root.left), maxDepth(root.right));
}Tradeoff:
Udemy-specific tips
Udemy asks about e-learning recommendation systems, content search, and marketplace algorithms — balanced mix of arrays, hash maps, and dynamic programming problems.
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