5. Remove Element
easyAsked at GojekRemove all occurrences of a value in-place from an array and return the new length.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an integer array nums and an integer val, remove all occurrences of val in-place. Return the count k of remaining elements; the first k slots of nums must contain the survivors in any order.
Constraints
0 <= nums.length <= 1000 <= val <= 100
Examples
Example 1
nums = [3,2,2,3], val = 32, nums = [2,2,_,_]Example 2
nums = [0,1,2,2,3,0,4,2], val = 25Approaches
1. Filter rebuild
Filter and write back.
- Time
- O(n)
- Space
- O(n)
const keep = nums.filter(x => x !== val);
for (let i = 0; i < keep.length; i++) nums[i] = keep[i];
return keep.length;Tradeoff:
2. Two pointers in-place
Write pointer advances only when current value isn't val; everything else gets overwritten.
- Time
- O(n)
- Space
- O(1)
function removeElement(nums, val) {
let k = 0;
for (let i = 0; i < nums.length; i++) {
if (nums[i] !== val) {
nums[k] = nums[i];
k++;
}
}
return k;
}Tradeoff:
Gojek-specific tips
Gojek interviewers reward concise two-pointer solutions because their ride-status arrays churn frequently and need predictable mutation behavior.
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