5. Remove Element
easyAsked at WiseRemove all occurrences of a value in place — Wise frames this as scrubbing a failed-transfer flag from a batch payout array before settlement.
By Alex Chen, Founder, InterviewChamp.AI · Last verified
Problem
Given an integer array nums and an integer val, remove all occurrences of val in nums in place. Return the number of elements not equal to val.
Constraints
0 <= nums.length <= 1000 <= nums[i] <= 500 <= val <= 100
Examples
Example 1
nums=[3,2,2,3], val=32 (nums=[2,2,_,_])Example 2
nums=[0,1,2,2,3,0,4,2], val=25 (nums=[0,1,3,0,4,_,_,_])Approaches
1. Filter and copy
Filter into a new array then copy back.
- Time
- O(n)
- Space
- O(n)
const kept = nums.filter(x=>x!==val); for(let i=0;i<kept.length;i++) nums[i]=kept[i]; return kept.length;Tradeoff:
2. Two pointers
Write pointer trails; skip the bad value.
- Time
- O(n)
- Space
- O(1)
function removeEl(nums,val){
let k=0;
for (let i=0;i<nums.length;i++){
if (nums[i]!==val) nums[k++]=nums[i];
}
return k;
}Tradeoff:
Wise-specific tips
Wise grades whether you remember the in-place constraint — settlement batches are huge and copy-allocations bite at scale.
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